I am working on a third-party REST API and I am going to authenticate with their API by making a POST request to the provided end point. I tested this end point using Postman and it works fine, and now I wanted to do it programmatically.
I am using Spring boot 3.0 for development and RestTemplate
as the http client. The code I have implemented is below, it gives me a 415 UNSUPPORTED_MEDIA_TYPE
error.
HttpHeaders headers = new HttpHeaders();
headers.add("Authorization", "Basic xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx==");
headers.add("Accept", "application/json");
headers.add("Content-Type","application/x-www-form-urlencoded");
MultiValueMap<String, String> requestBody = new LinkedMultiValueMap<String, String>();
requestBody.add("grant_type", "client_credentials");
HttpEntity formEntity = new HttpEntity<MultiValueMap<String, String>>(requestBody, headers);
String serverEndPoint = "https://xxxxxxx.xxx/auth/oauth2/xx/token";
ResponseEntity<String> response = restTemplate.exchange(serverEndPoint, HttpMethod.POST,formEntity, String.class);
System.out.println(response.getStatusCode().value());
Build RestTemplate
@Bean
public RestTemplate getRestTemplate() {
RestTemplate restTemplate = new RestTemplate();
restTemplate.setErrorHandler(new DefaultResponseErrorHandler() {
@Override
public void handleError(ClientHttpResponse response) throws IOException {
// don't throw
}
});
return restTemplate;
}
But same logic I have implemented using Jersey http client as mentioned below, it gives me successful response with 200 response code.
JacksonJsonProvider jacksonJsonProvider = new JacksonJaxbJsonProvider()
.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
Client client = ClientBuilder.newClient(new ClientConfig(jacksonJsonProvider));
Form form = new Form();
form.param("grant_type", "client_credentials");
String serverEndPoint = "https://xxxxxxx.xxx/auth/oauth2/xx/token";
Response response = client.target(serverEndPoint)
.request("application/json")
.header("Authorization", "Basic xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx==")
.post(Entity.entity(form, APPLICATION_FORM_URLENCODED));
System.out.println(response.getStatus());
Kindly help me to resolve this since I need to move forward with the RestTemplate client.
cUrl From Postman
curl --location --request POST 'https://xxxxxxxxxxxxx.xxx/auth/oauth2/xx/token' \
--header 'Content-Type: application/x-www-form-urlencoded' \
--header 'Authorization: Basic xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx==' \
--header 'Cookie: coolie data bla bla' \
--data-urlencode 'grant_type=client_credentials'
CodePudding user response:
If I inspect what the successful calls (curl and the Jersey HttpClient) send to the server vs what RestTemplate.exchange() sends, the only significant difference is that RestTempate.exchange() appends the charset=utf-8 to the Content-Type header.
I suspect that the sever you are calling is too strict on Content-Type and throws a 415 if it does not match "application/x-www-form-urlencoded" exactly.
To prevent this you need to use RestTempate.postForObject() instead. Try changing your RestTemplate call code as follows:
String serverEndPoint = "https://httpbin.org/post";
HttpHeaders headers = new HttpHeaders();
headers.setAccept(Arrays.asList(MediaType.APPLICATION_JSON));
headers.setContentType(MediaType.APPLICATION_FORM_URLENCODED);
HttpEntity<String> entity = new HttpEntity<>("grant_type=client_credentials", headers);
String result = restTemplate.postForObject( serverEndPoint, entity, String.class);
The MediaType
is org.springframework.http.MediaType
.
Note that I call httpbin.org in the code fragment. I find it extremely useful in researching an issue like this.