Python parameter Settings-CodePudding

Dear love, this is I consult a B standing of a net friend, because of my poor in station B discussion, borrow BBS consult him, so you may see don't understand, trouble you pass by me alone,

 import re 
Headers_str='type: a typ: b type: c' 
The pattern='^ (. *?) : (. *) $' 
For the line in headers_str. Splitlines () : 
Print (re. Sub (pattern, 1 \ '\' \ \ ', \ '\ \ \', '2, line))

Output the result is:

'type' : 'a typ: b type: c',

Consult, whether to fill parameters one by one?

Such as: type: a, enter the correct key values. Then input the type: b? Not a one-time to get these parameters are in

CodePudding user response:

Li=list (input ())
Eaders_str="/" type: {0} typ: {1} type: {2}/'". The format (li [0], li [1], li [2])

CodePudding user response:

The import re
Headers_str="" "
Ie: utf-8
Kw: python
Fid: 155829
Dar: 0
Vcode_md5:
Floor_num: 0
Rich_text: 1
TBS: af831780349117231592294109
Content: 1111
The basilisk: 1
Title:
The prefix:
121120124102114122115126,67,123,102,122,102,123,102,122,102,123,102,122,102,123,102,122,102,123,102,122,67,123,120,127,127,126,114,67,123,127,121,124,102,114,124,126,15922941206741 mouse_pwd:
Mouse_pwd_t: 1592294120674
Mouse_pwd_isclick: 1
Nick_name: post bar user _5JUJtX1
__type__ : thread
Geetest_success: 0
_BSK: 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

"" "
The pattern='^ (. *?) : (. *) $'
For the line in headers_str. Splitlines () :
Print (re. Sub (pattern, 1 \ '\' \ \ ', \ '\ \ \', '2, line))