In python exclusive or ask the following questions:

If I have a set of Numbers, a digital have arisen only once, other appear twice, that how to find the appear a number?

CodePudding user response:

For example, unclear meaning

CodePudding user response:

 s=,1,6,2,2,3,3,4,4,5,5 [1] 
Dict1={} 
For x in s: 
If dict1. Get (x, 'FFFF)==' FFFF ': 
Dict1 [x]=1 
The else: 
Dict1 [x] +=1 
Print (dict1) 
Print (list ([x, dict1 [x]] for x in dict1. Keys () if dict1 [x]==1)) 

CodePudding user response:

 
S=,1,6,2,2,3,3,4,4,5,5,7 [1] 
Dict1={} 
For x in s: 
If dict1. Get (x, 'FFFF)==' FFFF ': 
Dict1 [x]=1 
The else: 
Dict1 [x] +=1 
Print (dict1) 
Print (list ([x, dict1 [x]] for x in dict1. Keys () if dict1 [x]==1)) 

Dict1={} 
For x in s: 
Dict1 [x]=dict1. Setdefault (x, 0) + 1 
Print (dict1) 
Print (list ([x, dict1 [x]] for x in dict1. Keys () if dict1 [x]==1)) 

CodePudding user response:

Is this meaning?

 
LST=(1, 1, 6, 2, 2, 3, 3, 4, 4, 5, 5, 7] 
Once_num=filter (lambda x: LST. The count (x)==1, LST) 
Print (list (once_num))