Python sort merge-CodePudding

List=[[' ABC ', 6], [' BCD, 3], [' BCD, 2]]

How to sort merge, want to output is as follows:

List=[[' ABC ', 6], [' BCD, 5]]

Modify the original list or create a new list can be
How do I achieve?

CodePudding user response:

 list1=[[' ABC ', 6], [' BCD, 3], [' BCD, 2]] 
Dic={} 
For the item in list1: 
If the item [0] not in dic: 
Dic [item [0]]=item [1] 
The else: 
Dic [item [0]] +=item [1] 
List_new=[(x, y) for the x, y in dic. The items ()]

CodePudding user response:

reference 1st floor Bluebluesea response:

 list1=[[' ABC ', 6], [' BCD, 3], [' BCD, 2]] 
Dic={} 
For the item in list1: 
If the item [0] not in dic: 
Dic [item [0]]=item [1] 
The else: 
Dic [item [0]] +=item [1] 
List_new=[(x, y) for the x, y in dic. The items ()]

This dictionary can continue to use a derived type

 ls=[[' ABC ', 6], [' BCD, 3], [' BCD, 2]] 
Dc dict () 
For k, v in ls. __iter__ () : 
If k=v dc [k] not in dc else dc [k] + v 
Print ([[k, v] for k, v in dc. The items ()])

CodePudding user response:

 
List1=[[' ABC ', 6], [' BCD, 3], [' BCD, 2]] 

List2=list (set ([x [0] for x in list1])) 
Print ([[0] * len (list2)]) 
Dict1=dict (zip (list2, [0] * len (list2))) 
For x in list1: 
Dict1 [0] [x]=dict1 [0] [x] + [1] x 
Print (dict1) 

Dict2={} 
For x in list1: 
If dict2. Get (x [0], "FFF")=='FFF' : 
Dict2 [0]] to [x=x [1] 
The else: 
Dict2 [0] [x]=dict2 [0] [x] + [1] x 
Print (dict2)

CodePudding user response:

 ls=[[' ABC ', 6], [' BCD, 3], [' BCD, 2]] 
Dc={} 
For k, v in ls. __iter__ () : 
If k=v dc [k] not in dc else dc [k] + v 
Print (dc) 

Ls=[[' ABC ', 6], [' BCD, 3], [' BCD, 2]] 
Dc dict () 
For k, v in ls. __iter__ () : 
If k=v dc [k] not in dc else dc [k] + v 
Print (dc)

Should also can

CodePudding user response:

refer to the second floor slap-happy explode response:

Quote: refer to 1st floor Bluebluesea response:

 list1=[[' ABC ', 6], [' BCD, 3], [' BCD, 2]] 
Dic={} 
For the item in list1: 
If the item [0] not in dic: 
Dic [item [0]]=item [1] 
The else: 
Dic [item [0]] +=item [1] 
List_new=[(x, y) for the x, y in dic. The items ()]

This dictionary can continue to use a derived type

 ls=[[' ABC ', 6], [' BCD, 3], [' BCD, 2]] 
Dc dict () 
For k, v in ls. __iter__ () : 
If k=v dc [k] not in dc else dc [k] + v 
Print ([[k, v] for k, v in dc. The items ()])

Can you further simplification of the some

CodePudding user response:

reference 5 floor Bluebluesea reply:

Quote: refer to the second floor slap-happy explode response:

Quote: refer to 1st floor Bluebluesea response:

list1=[[' ABC ', 6], [' BCD, 3], [' BCD, 2]]
Dic={}
For the item in list1:
If the item [0] not in dic:
Dic [item [0]]=item [1]
The else:
Dic [item [0]] +=item [1]
List_new=[(x, y) for the x, y in dic. The items ()]

This dictionary can continue to use a derived type
ls=[[' ABC ', 6], [' BCD, 3], [' BCD, 2]]
Dc dict ()
For k, v in ls. __iter__ () :
If k=v dc [k] not in dc else dc [k] + v
Print ([[k, v] for k, v in dc. The items ()])

Can be, the more you simplify some

Can also simplify again

CodePudding user response:

refer to 6th floor goofs off explode reply:

Quote: refer to the fifth floor Bluebluesea reply:

Quote: refer to the second floor slap-happy explode response:

Quote: refer to 1st floor Bluebluesea response:

list1=[[' ABC ', 6], [' BCD, 3], [' BCD, 2]]
Dic={}
For the item in list1:
If the item [0] not in dic:
Dic [item [0]]=item [1]
The else:
Dic [item [0]] +=item [1]
List_new=[(x, y) for the x, y in dic. The items ()]

This dictionary can continue to use a derived type
ls=[[' ABC ', 6], [' BCD, 3], [' BCD, 2]]
Dc dict ()
For k, v in ls. __iter__ () :
If k=v dc [k] not in dc else dc [k] + v
Print ([[k, v] for k, v in dc. The items ()])

Can be, the more you simplify some

Please can also simplify

I feel as if I had no more simplified

CodePudding user response:

Quote: refer to 7th floor Bluebluesea response:

Find a best simplified derivation of type

 ls=[[' ABC ', 6], [' BCD, 3], [' BCD, 2]] 
Dc dict () 
[dc. Update (} {k: v). If k is not in dc else dc update (} {k: dc [k] + v) for k, v in the ls] 
Print ([[k, v] for k, v in dc. The items ()]) 
Print (dc)

CodePudding user response:

 import itertools as it 

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