In the instruction system, why can't a source and destination operand for storage at the same time, the most fundamental reason is what? Associated with the hardware?

CodePudding user response:

Associated with addressing mode bit set, both sides are all registers and memory patterns together, don't have so many place addressing mode, practice, can push/pop instructions to memory, is the same as a memory,

CodePudding user response:

Is technically can completely, but if you allow memory to memory, operation instructions coding will be long, efficiency drops

CodePudding user response:

8086 hardware no circuit from register to register