If a n the number of digits of n is equal to the sum of the number itself, is referred to as n wang needed, all wang needed for between 100 ~ 10000000 deposit to a list, and output

CodePudding user response:

The name haha

 

# 100 ~ 10000000 n wang needed several 
N_list=[] 
For I in range (100100000 0 + 1) : 
Sum=0 
For j in STR (I) : 
The sum +=int len (j) * * (STR) (I) 
If I==sum: 
N_list. Append (I) 
Print (n_list)