For 24 full-color images, is "the sum of all the colors of each pixel component of binary digits" equal to 24, so the three channels of R, G, B share this 24 storage space, namely each channel 8,
My question is as follows: for 8-bit color (256 colors) images, a total of only 8 bits of storage space, how to allocate 3 channels? Don't be evenly distributed?

CodePudding user response:

8 bit depth is single channel, only black and white

CodePudding user response:

General 8 bit for the gray image, if the full color need to line up with the RGB, three 8 than he said one pixel