The 192.168.1.0, divided into four subnets, each subnet network address, the broadcast address, can assign IP addresses, the latest subnet mask

CodePudding user response:

Said this is very simple, only the last one, in binary, and then converted to a decimal, four subnets, number of wire is represented with two child, behind the number six is machine
First subnet: 00 period of 00000000 ~ 00111111
The second subnet: 01 period of 01000000 ~ 01111111
The third subnet: 10 period of 10000000 ~ 10111111
The fourth subnet: 11 period of 11000000 ~ 11111111

CodePudding user response:

First look at a book club, specific ask, someone wrote the answer after you or not

CodePudding user response:

refer to the second floor weixin_40290083 response:

a good look at the book, first, specific ask others to write the answer after you still wouldn't

I understand

CodePudding user response:

Network addresses, 192.168.1.0, the broadcast address, 192.168.1.63
Can assign IP, 192.168.1.1-192.168.1.62, subnet mask, latest 255.255.255.192

CodePudding user response:

reference 4 floor weixin_45988947 response:

network addresses, 192.168.1.0, the broadcast address, 192.168.1.63
Can assign IP, 192.168.1.1-192.168.1.62, subnet mask, latest 255.255.255.192

that's right

CodePudding user response:

reference 5 floor Iforgetmyid reply:

Quote: refer to 4th floor weixin_45988947 response:

network addresses, 192.168.1.0, the broadcast address, 192.168.1.63
Can assign IP, 192.168.1.1-192.168.1.62, subnet mask, latest 255.255.255.192

right

Not easy to work out