Is there a built-in way to add a line connecting scatter points with the same y-val?
Currently have this:
x1 = [6, 11, 7, 13, 6, 7.5]
x2 = [np.nan, np.nan, np.nan, np.nan, np.nan, 8.6]
y = [2, 10, 2, 14, 9, 10]
df = pd.DataFrame(data=zip(x1, x2, y), columns=["x1", "x2", "y"])
fig, ax = plt.subplots()
ax.set_xlabel("x")
ax.set_ylabel("y")
ax.scatter(df["x1"], df["y"], c="k")
ax.scatter(df["x2"], df["y"], edgecolor="k", facecolors="none")
Want this:
CodePudding user response:
You can pair the points (x1[i],y[i]) and (x2[i],y[i]) iteratively by using the following code:
import numpy as np
import matplotlib.pyplot as plt
import pandas as pd
x1 = [6, 11, 7, 13, 6, 7.5]
x2 = [np.nan, np.nan, np.nan, np.nan, np.nan, 8.6]
y = [2, 10, 2, 14, 9, 10]
df = pd.DataFrame(data=zip(x1, x2, y), columns=["x1", "x2", "y"])
fig, ax = plt.subplots()
ax.set_xlabel("x")
ax.set_ylabel("y")
ax.scatter(df["x1"], df["y"], c="k")
ax.scatter(df["x2"], df["y"], edgecolor="k", facecolors="none")
for i in range(len(y)):
plt.plot([x1[i],x2[i]],[y[i],y[i]])
plt.show()
The output of this code gives: