How to pass a list to a function then sort and count the occurrence of items respectively using Pyth-CodePudding

With a list like this: ["Apple", "Banana", "Peach", "Apple", "Banana", "Orange"]

I tried to pass the list to a function and sort it as follows:

def l(fruits):
  for i in fruits:
    print(i)

n = ["Apple", "Banana", "Peach", "Apple", "Banana", "Orange"]

l(sorted(n))

I only got the result like this:

Apple
Apple
Banana
Banana
Orange
Peach

I am wondering how to count the occurrence of each item in the list respectively to get the output like this:

Apple 2
Banana 2
Orange 1
Peach 1

I know using collections.Counter can get a similar result, however, I would like the output to be the same as above.

Edit: I just found out the items in the list should be in lower case.

Also, I tried doing it without collections_counter

def fruit_list(fruits):
  for i in fruits:
    fruit_occurence = fruits.count("apple")
    fruit_occurence2 = fruits.count("banana")
    fruit_occurence3 = fruits.count("peach")
    fruit_occurence4 = fruits.count("orange")
    if i == "apple":
      print(i.title(), *{fruit_occurence})
    elif i == "banana":
      print(i.title(), *{fruit_occurence2})
    elif i == "peach":
      print(i.title(), *{fruit_occurence3})
    elif i == "orange":
      print(i.title(), *{fruit_occurence4})


f = ["apple", "banana", "peach", "apple", "banana", "orange"]

fruit_list(sorted(f))

Output:

Apple 2
Apple 2
Banana 2
Banana 2
Orange 1
Peach 1

Is there anyway to remove the duplicate items in the output? Changing the list to set would affect the fruit_occurances.

CodePudding user response：

You can use Counter then use sorted in for in function then use print(*...) like below:

from collections import Counter

def l(fruits):
    for i in sorted(Counter(fruits).items()):
        print(*i)

n = ["Apple", "Banana", "Peach", "Apple", "Banana", "Orange"]

l(n)

Output:

Apple 2
Banana 2
Orange 1
Peach 1

CodePudding user response：

Use a collections.Counter:

from collections import Counter


def l(fruits):
    c = Counter(fruits)
    for fruit, count in sorted(c.items()):
        print(fruit, count)

CodePudding user response：

Without modifying l at all,

>>> l(f'{f} {c}' for f, c in sorted(Counter(n).items()))

The trick is to create a generator expression that produces the strings you want to print from the Counter instance.

CodePudding user response：

text = ["Apple", "Banana", "Peach", "Apple", "Banana", "Orange"]
dict = {}
def l(text):
   for i in text:
       dict[i] = text.count(i)
   print(dict)
l(text)

CodePudding user response：

This should be work for you

import collections

fruits = ["Apple", "Banana", "Peach", "Apple", "Banana", "Orange"]
d = {}
for fruit in fruits:
  if fruit in d:
    d[fruit]  = 1
  else:
    d[fruit] = 1

od = collections.OrderedDict(sorted(d.items()))
print (od)