Form a number according to the given conditions-CodePudding

Given three single digit numbers, write a code to find the largest number with smallest middle digit. For example, given the input as 3, 9, 8 the number to be formed is 938.

Input Format

First line contains the first single digit number, d1

Next line contains the second single digit number, d2

Next line contains the third single digit number, d3

Output Format

Print the number formed

Why is my code wrong?

d1=int(input())
d2=int(input())
d3=int(input())
lists=[d1,d2,d3]
y=lists.sort()
a=y[2]
b=y[1]
c=y[0]
num=(int(a)*100) (int(c)*10) int(b)
print(num)

CodePudding user response：

.sort() modifies the original list without returning a value, what you want here is this:

d1=int(input())
d2=int(input())
d3=int(input())
lists=[d1,d2,d3]
lists.sort()
a=lists[2]
b=lists[1]
c=lists[0]
num=(int(a)*100) (int(c)*10) int(b)
print(num)