regex for "finding whole word only" plus allowing one character-CodePudding

Hi I'm using this regular expression to find whole word only: example:

Dim oRE, bMatch
Set oRE = New RegExp
oRE.Pattern = "\bFunction\b"
bMatch = oRE.Test("Functions") 'return false
bMatch = oRE.Test("Function dummy") 'return true

I want to allow one character at the end of the string. The char i want to allow is the double quote ("). So i would like this line of code to return true:

bMatch = oRE.Test("Function" chr(34) " dummy") 'chr(34) is the charcode of doublequote (")

CodePudding user response：

Initiate a variable with chr(34) and concatenate it into your pattern.

dq = Chr(34)
oRE.Pattern = "\bFunction" & dq & " \b"

Then you will be able to match the double quotes as well.

for 1 or more double quotes after Function (modify it per your needs).

CodePudding user response：

The double quote can be written like this \x22 in order to replace it easily in your pattern "

Hope that this what you want as result Demo here

Dim oRE, bMatch
Set oRE = New RegExp
oRE.Pattern = "\bFunction. ?\x22"
aMatch = oRE.Test("Functions""")
bMatch = oRE.Test("Function dummy""")
wscript.echo "Functions " & aMatch
wscript.echo "Functions dummy " & bMatch