Small white primer for problem solving (extraction) vowels, don't know where is wrong, ask answ-CodePudding

#include
#include
Void letter (char x [20], char y [20])
{
Int n=strlen (x);
Int j;
For (int I=0, j=0; iIf (x [I]=='a' | | x [I]=='e' | | x [I]=='I' | | x [I]=='o' | | x [I]=='u' | | x [I]=='a' | | x [I]=='e' | | x [I]=='I' | | x [I]=='o' | | x [I]=='u') {
Y=x [j] [I];
j++;
}
}
int main () {
[20] char a, b [20].
Gets (a);
The letter (a, b);
Puts (b);
return 0;
}

11 of 13 C: \ Users \ Administrator \ \ Desktop \ \ C 2.6 vowels 2. CPP [Error] a function - definition is not allowed here before '{' token
1 C: \ Users \ \ Administrator \ \ Desktop \ \ C 2.6 vowels 2. CPP [Error] expected '} 'at the end of the input

CodePudding user response:

Curly braces to pairs, suggesting less} it is clear that the code to play good, you will find a less}, patch is,

 
Void letter (char x [20], char y [20]) 
{
Int n=strlen (x); 
Int j; 
For (int I=0, j=0; i{
If (x [I]=='a' | | x [I]=='e' | | x [I]=='I' | | x [I]=='o' | | x [I]=='u' | | x [I]=='a' | | x [I]=='e' | | x [I]=='I' | | x [I]=='o' | | x [I]=='u') 
{
Y=x [j] [I]; 
j++; 
} 
}

See a less}

CodePudding user response:

#include
#include
Void letter (char x [20], char y [20])
{
Int n=strlen (x);
int i, j;
For ( I=0, j=0 ; iIf (x [I]=='a' | | x [I]=='e' | | x [I]=='I' | | x [I]=='o' | | x [I]=='u' | | x [I]=='a' | | x [I]=='e' | | x [I]=='I' | | x [I]=='o' | | x [I]=='u') {
Y=x [j] [I];
j++;
}
}
y [j]='\ 0';
}
int main () {
[20] char a, b [20].
Gets (a);
The letter (a, b);
Puts (b);
return 0;
}
In addition to the letter function is missing a curly braces outside does not match the
For ( int I=0, j=0 ; Here will take j as redefining the local variable
Y array finally don't forget to the end of the string with 0, otherwise the main function of the puts (b) maybe output