How to convert a XML path into xml format in Python-CodePudding

I have a path "a/b/c/d" and value for d is Apple.

I would like to create a function to transform the path into XML format like:

<a>
 <b>
  <c>
   <d> Apple </d>
  </c>
 </b>
</a>

CodePudding user response：

A simple string-based solution could be

tags = "a/b/c/d".split('/')
value = 'Apple'

out = ''
for t in tags:
    out  = f'<{t}>'
out  = value
for t in reversed(tags):
    out  = f'</{t}>'

print(out) # <a><b><c><d>Apple</d></c></b></a>

CodePudding user response：

Solution using xml.etree.ElementTree, the advantage is that you can assign values to any element

from xml.etree import ElementTree

def xpath_to_xml(current_node, path, text_values):
    parts = path.split("/")
    while parts:
        target = 0
        part = parts.pop(0)
        cur = -1
        for child in current_node.getchildren():
            if child.tag == part:
                cur  = 1
                if cur == target:
                    node = child
                    break
        else:
            for _ in range(target - cur):
                new = ElementTree.Element(part)
                if part in text_values:
                    new.text = text_values[part]
                current_node.append(new)
            current_node = new


def main():
    doc = ElementTree.Element("root")
    xpath_to_xml(doc, "a/b/c/d", {"d": "Apple"})
    print(ElementTree.tostring(doc))