Confused on how the multiple variables work and how to get all 4 values from 1st item in list-CodePudding

testdata = ["One,For,The,Money", "Two,For,The,Show", "Three,To,Get,Ready", "Now,Go,Cat,Go"]

#My Code:
def chop(string):
    x = 0
    y = 0
    while x < 5:
        y = string.find(",")   1
        z = string.find(",", y)
        x = x   1

    return y, z
#My Code Ends

for i in range(4):
    uno, dos, tres, cuatro = chop(testdata[i])
    print(uno   ":"   dos   ":"   tres   ":"   cuatro)

It say I don't have enough values, I previously tried appending similar code to a list and it said I had too many

CodePudding user response：

I cant figure out why You need to do in that way, but maybe it helps.

testdata = ["One,For,The,Money", "Two,For,The,Show",
        "Three,To,Get,Ready", "Now,Go,Cat,Go"]

for i in testdata:
    uno, dos, tres, cuatro = i.split(',')
    print(uno   ":"   dos   ":"   tres   ":"   cuatro)

Result

One:For:The:Money
Two:For:The:Show
Three:To:Get:Ready
Now:Go:Cat:Go

Just iterate through array and spllit words by ,. Result is as expected.

CodePudding user response：

You can search for the position of the , (comma) in the given line and apply sweeping technique to insert the words into a list. You were getting too few values as the function was not returning 4 elements that is being extracted in the for loop.

testdata = ["One,For,The,Money", "Two,For,The,Show", "Three,To,Get,Ready",
            "Now,Go,Cat,Go"]


# My Code:
def chop(line):
    start_position = 0
    words = []
    for i, c in enumerate(line):
        if c == ",":
            words.append(line[start_position:i])
            start_position = i 1
    words.append(line[start_position:])
    return words


# My Code Ends

for i in range(4):
    uno, dos, tres, cuatro = chop(testdata[i])
    print(uno   ":"   dos   ":"   tres   ":"   cuatro)

Output:

One:For:The:Money
Two:For:The:Show
Three:To:Get:Ready
Now:Go:Cat:Go

Explanation:

Here we are keeping the start position of each word in the start_position variable.