Python socket returning different IP address for the same host name in local and server-CodePudding

I am trying to get the IP address from the domain name, the problem is it gives a different IP address when the code is running locally and on the server.

Here is my code and the result when running on local

import socket
domain_str="use.typekit.net"
ip = socket.gethostbyname(domain_str.strip())
print(ip)

output > '104.86.189.35'

Here is the result of the same code running on the server

output > '62.115.253.9'

I would really appreciate it if anyone could let me know why this is happening.

CodePudding user response：

The server you are trying to reach is behind the Akamai CDN. Depending on where you connect from this CDN might give you a different IP address for optimal connectivity.

For example I get from one location:

$ dig use.typekit.net
...
use.typekit.net.        121     IN      CNAME   use-stls.adobe.com.edgesuite.net.
use-stls.adobe.com.edgesuite.net. 5853 IN CNAME a1988.dscg1.akamai.net.
a1988.dscg1.akamai.net. 133     IN      A       89.27.242.17
a1988.dscg1.akamai.net. 133     IN      A       89.27.242.41

while from another location

use.typekit.net.        28      IN      CNAME   use-stls.adobe.com.edgesuite.net.
use-stls.adobe.com.edgesuite.net. 21568 IN CNAME a1988.dscg1.akamai.net.
a1988.dscg1.akamai.net. 5       IN      A       104.114.77.65
a1988.dscg1.akamai.net. 5       IN      A       104.114.77.32

If you do a GeoIP lookup of these addresses you will see one of your addresses located in India while the other one in Sweden.