C language function int divide (char * ss, int * a), its function is: from left to right in turn ss-CodePudding

Write function int divide (char * ss, int * a), its function is: from left to right in turn ss scan the string will be continuous string of Numbers into an integer, and, in turn, save it to a point in the array, the function returns a number of integer in the array to save

In the main function of the main through a call to divide function and getSum function calculating the Numbers in a given string consisting of a number of integers and,

L input line of string does not exceed 80 characters, conditions should be considered negative integers

# include & lt; Stdio. H>
# include & lt; Stdlib. H>
# include & lt; Ctype. H>

Int divide (char * ss, int * a);
Int getSum (int * a, int n);

Int main ()
{
Char ss [100].
Int a [100], n, sum;
Gets (ss);
N=divide (ss, a);
Sum=getSum (a, n);
Printf (" % d \ n ", sum);
Return 0;
}
Int divide (char * ss, int * a)
{

}
Int getSum (int * a, int n)
{
Int sum=0, I;
for(i=0; iSum=sum + a [I];
}
Return the sum.
}

CodePudding user response:

Reference:

 # include & lt; Iostream. H> 
#include  
Int divide (char * ss, int * a) 
{
Int j, n=0, I, k; 
Char \ [100]. 
for (i=0; Ss [I]!='\ 0'; I++) 
{
J=0; 
While (ss [I] & gt;='0' & amp; & Ss [I] <='9' | | ss [I]=='-') 
{
Temp=ss [j] [I]; 
j++; 
i++; 
} 
If (j!=0) 
{
Temp [j]='\ 0'; 
* a=atoi (temp); 
a++; 
n++; 
i--; 
} 

} 
return n; 
} 

Int getSum (int * a, int n) 
{
Int sum=0, I; 
for(i=0; iThe sum +=a [I]; 
Return the sum. 
} 

Int main (int arg c, char * argv []) 
{
Char ss [100]. 
Int n, sum=0, a, [100]. 
Gets (ss); 
CoutN=divide (ss, a); 
Sum=getSum (a, n); 
Cout<" Sum="& lt; System (" pause "); 
return 0; 
}

CodePudding user response:

 # include & lt; Stdio. H> 
# include & lt; Stdlib. H> 
# include & lt; Ctype. H> 

Int divide (char * ss, int * a); 
Int getSum (int * a, int n); 

Int main () 
{
Char ss [100]. 
Int a [100], n, sum; 
The fgets (ss, 100, stdin); 
N=divide (ss, a); 
Sum=getSum (a, n); 
Printf (" % d \ n ", sum); 

Return 0; 
} 

Int divide (char * ss, int * a) 
{
Char * p=ss; 
Int num=1, I, sign; 

Sign=1; 
i=0; 
While (* p) {
While (* p & amp; & Isdigit (* p)) {
If (num & lt; 0 {
If (p - ss & gt;=1 & amp; & * (p - 1)=='-') 
Sign *=1; 
Num=0; 
} 
Num=(num * 10) + * p - '0'; 
P++; 
} 
If (num & gt;=0) {
A [i++]=num * sign; 
Num=1; 
Sign=1; 
} 
If (* p=='\ 0') 
break; 
P++; 
} 

return i; 
} 
Int getSum (int * a, int n) 
{
Int sum=0, I; 
for(i=0; iSum=sum + a [I]; 
} 
Return the sum. 
}

For your reference ~

CodePudding user response:

Before a flawed handling the negative, modified as follows, for reference:

 # include & lt; Iostream. H> 
#include  
Int divide (char * ss, int * a) 
{
Int j, n=0, I, k; 
Char \ [100]. 
for (i=0; Ss [I]!='\ 0'; I++) 
{
J=0; 
K=0; 
While (ss [I] & gt;='0' & amp; & Ss [I] <='9') 
{
If (k==0 & amp; & Ss [I - 1]=='-')//negative processing 
{
Temp=ss [j] [I - 1); 
j++; 
k++; 
} 
Temp=ss [j] [I]; 
j++; 
i++; 
} 
If (j!=0) 
{
Temp [j]='\ 0'; 
* a=atoi (temp); 
a++; 
n++; 
i--; 
} 

} 
return n; 
} 

Int getSum (int * a, int n) 
{
Int sum=0, I; 
for(i=0; iThe sum +=a [I]; 
Return the sum. 
} 

Int main (int arg c, char * argv []) 
{
Char ss [100]. 
Int n, sum=0, a, [100]. 
Gets (ss); 
N=divide (ss, a); 
Sum=getSum (a, n); 
Cout<" Sum="& lt; 
System (" pause "); 
return 0; 
}

CodePudding user response:

reference QZJHJXJ reply: 3/f

before a flawed handling the negative, modified as follows, for reference:

 # include & lt; Iostream. H> 
#include  
Int divide (char * ss, int * a) 
{
Int j, n=0, I, k; 
Char \ [100]. 
for (i=0; Ss [I]!='\ 0'; I++) 
{
J=0; 
K=0; 
While (ss [I] & gt;='0' & amp; & Ss [I] <='9') 
{
If (k==0 & amp; & Ss [I - 1]=='-')//negative processing 
{
Temp=ss [j] [I - 1); 
j++; 
k++; 
} 
Temp=ss [j] [I]; 
j++; 
i++; 
} 
If (j!=0) 
{
Temp [j]='\ 0'; 
* a=atoi (temp); 
a++; 
n++; 
i--; 
} 

} 
return n; 
} 

Int getSum (int * a, int n) 
{
Int sum=0, I; 
for(i=0; iThe sum +=a [I]; 
Return the sum. 
} 

Int main (int arg c, char * argv []) 
{
Char ss [100]. 
Int n, sum=0, a, [100]. 
Gets (ss); 
N=divide (ss, a); 
Sum=getSum (a, n); 
Cout<" Sum="& lt; 
System (" pause "); 
return 0; 
}

nullnullnullnullnullnullnullnullnullnullnull