Ask why the short in the for loop (c, a, b, Y, X) can output nor assignment, but the diatance (0, Y,-CodePudding

#include
#include
using namespace std;
Double short (int x, int y, int z, int y [], int x []) {double k=double ((y [y] - [z] y)/(x [y] -x [z])); Double b=double (Y/Y - k * X [Y]);
Return a double (fabs (k * X [X] - [X] Y + b)/SQRT (k * k + 1));
}
Int main () {
Int n, x, y;
Cin> n;
Int X [n], [n] Y;
Int beauty [n]={0};
for(int i=0; ICin> x> y;
[I]=X X;
[I] Y=Y;
}
For (int a=0; AFor (int b=a + 1; BDouble min;
For (int c=0; CIf ((c!=a) & amp; & (c!=b)) {
//min=short (c, a, b, Y, X);
//cout}
/* for (int d=c + 1; DIf ((short (d, a, b, Y, X) & lt; Min) & amp; & (d!=a) & amp; & (d!=b)) {
Min=short (d, a, b, Y, X);
}
} */
}
/*
For (int e=0; EIf (short (e, a, b, Y, X)==min) {
=beauty beauty [e] [e] + 1;
}
} */
}
}
//coutreturn 0;
}