Extracting URL From Span Element Without href-CodePudding

I am attempting to extract links from a website that does not use a href. I have tried multiple iterations of trying to find the tag associated with the url that from what I can gather is between <span> elements.

import requests
from bs4 import BeautifulSoup

url = 'https://www.flavortownusa.com/locations'

page = requests.get(url)
f = open("test12.csv", "w")

soup = BeautifulSoup(page.content, 'html.parser')

lists = soup.find_all('div', class_ = 'listing-item-inner')

for list in lists:
    title = list.find('span', class_ = '$0')
    webs = list.find('#text', class_ = 'fa-fa.link')
    address = list.find('ul', class_ = 'post-meta')
    temp = list.find('span', class_ = 'text')
    temp2 = list.find('i', class_ = '(text)')
    info = [title, webs, address, temp, temp2]
    f.write(str(info))
    f.write("\n")

    print(info)

The desired output is to extract data from <span></span> where the 345 40th Ave N and the url below i class = 'fa fa-link' and i class = 'fa fa-phone' where the three elements are placed into a CSV File

CodePudding user response：

You could call next element e.find(class_ = 'fa-link').nextafter selecting the <i> with class fa-link:

for e in lists:
    print(e.find(class_ = 'fa-link').next.strip() if e.find(class_ = 'fa-link') else '')

Note: Do not use reserved keywords like list and always check if element you are searching for is available.

Example

import requests
from bs4 import BeautifulSoup

url = 'https://www.flavortownusa.com/locations'
soup = BeautifulSoup(page.content, 'html.parser')


with open('somefile.csv', 'a', encoding='utf-8') as f:
    
    for e in soup.find_all('div', class_ = 'listing-item-inner'):
        title = e.h3.text
        webs = e.select_one('.fa-link').next if e.select_one('.fa-link') else ''
        address = e.span.text
        phone = e.select_one('.fa-phone').next if e.select_one('.fa-phone') else ''

        f.write(','.join([title, webs, address, phone]) '\n')