Set position for player from variable in Unity-CodePudding

Me need set random position in Start() for player as minecraft.

Player already have the script, but position don't change of default.

Error in 24 and 25 string.

Code:


using UnityEngine;

public class RandomRespawn : MonoBehaviour
{
    [Header("Игрок")] // player
    public GameObject Player;

    [Header("Объявление координат")] // have position
    public int positionX;
    public int positionZ;

    [Header("Рандомные координаты")] // random position
    public int randomPosX;
    public int randomPosZ;

    private void Start()
    {
        System.Random randomPos = new System.Random();
        Vector3 positions = transform.position;

        positionX = randomPos.Next(1, 50);
        positionZ = randomPos.Next(1, 50);

        gameObject.positions.x = positionX;
        gameObject.positions.z = positionZ;
    }
}

I have error: (25,20): error CS1061: 'GameObject' does not contain a definition for 'positions' and no accessible extension method 'positions' accepting a first argument of type 'GameObject' could be found (are you missing a using directive or an assembly reference?), now =(

CodePudding user response：

To change the position of the attached player gameobject, you need to change this:

gameObject.positions.x = positionX;
gameObject.positions.z = positionZ;

To this:

Player.transform.position = new Vector3(positionX, positionZ, Player.transform.position.z);

CodePudding user response：

You can't get the position properties from GameObject, you need to get the position from Transform properties.

And you can't directly set the value of position.x directly from a float value. You must create a new Vector3 variable and set the value first. And then you can apply that variable value to your transform.position.