Delete files from folder except one in Bash-CodePudding

I need to add a script which will delete files from directory before installation of new version. I need save from directory one catalog - /logs and all files inside ( inside we have *.log and *.zg files)

Ive created this line : find /directory/path/* ! -name 'logs' -type d,f -exec rm -r -v {} But in Debian 11 Its cleaning also my files inside of catalog log. Do you know what can be a reason ?

It works on zsh on macbook m1 and is not cleaning my log catalog.

Take Care : )

Expectation bash script which delete all catalogs and files from given directory EXCEPT one catalog /log and all files inside ( inside we have *.log and *.zg files) .

CodePudding user response：

Consider:

$ find . ! -name logs
.
./logs/a
./foo
./foo/a

The issue here is that although the directory logs matches the primary -name logs, the name a in logs does not. So find operates on that file. Rather than negating the -name primary, you want to match the logs directory and prune that from the find:

$ find . -name logs -prune -o -print
.
./foo
./foo/a

Also note that instead of find /directory/path/* ..., you almost certainly want find /directory/path .... There's no need to pass all of the names in /directory/path as arguments to find, and indeed that is ... weird. Just pass the top level dir and let find handle the tree descent.

CodePudding user response：

Maybe extended globbing.

shopt -s extglob
rm -frv /directory/path/!(logs)