show amount of Instagram followers on website-CodePudding

It seems like Instagram has changed certain things, because I have tried several codes on my html website to show the amount of Instagram followers on a button, but nothing works.

I tried this:

<?php
$account='XXX';
$instagramsource=file_get_contents('https://instagram.com/' . $account);
preg_match_all('/"userInteractionCount":"(.*?)"/', $instagramsource, $count);
$followcount=$count[1][0];
echo "$account instagram account has $followcount followers";
?>

Also this

<?php
$otherPage = 'XXX';
$response = file_get_contents("https://www.instagram.com/$otherPage/?__a=1");
if ($response !== false) {
$data = json_decode($response, true);
if ($data !== null) {
    $follows = $data['graphql']['user']['edge_follow']['count'];
    $followedBy = $data['graphql']['user']['edge_followed_by']['count'];
    echo $follows . ' and ' . $followedBy;
}
}
?>

And this ...

<?php
$url = "https://www.instagram.com/XXX";
$json = file_get_contents($url);
$obj = json_decode($json, true);
$content = $obj['query']['results']['script']['content'];
$content = str_replace("window._sharedData =", "", $content);
$content = str_replace(";", "", $content);
$content = trim($content);
$json = json_decode($content);
$instagram_follower_count = $json->entry_data->ProfilePage{0}->user->followed_by->count;
?>

And finally this:

<?php
$username = 'XXX';
$response = @file_get_contents( "https://www.instagram.com/$username/?__a=1" );
if ( $response !== false ) {
$data = json_decode( $response, true );
if ( $data !== null ) {
    $follows = $data['graphql']['user']['edge_follow']['count'];
    $followedBy  = $data['graphql']['user']['edge_followed_by']['count'];
    echo 'XXX follows:' . $follows . ' and is followed by: ' . $followedBy;
}
}
?>

None works. Can anyone indicate what would work in 2021, please? Thanks.

CodePudding user response：

It's because the url https://www.instagram.com/$username/?__a=1 is redirecting to login page & giving u a html response

You can check it by echo $response

CodePudding user response：

Instagram blocked access via __a=1 parameter since 2018-04-12. __a=1 must be replaced by JS and Ajax bypass. I've looked for an alternative solution. You can use javascript code inside php. For example:

async function instagramFollowers () {
    
    const followers = []
    
    try {
        const userInfoSource = await Axios.get('https://www.instagram.com/123/')

        
        const jsonObject = userInfoSource.data.match(/<script type="text\/javascript">window\._sharedData = (.*)<\/script>/)[1].slice(0, -1)

        const userInfo = JSON.parse(jsonObject)
       
        const mediaArray = userInfo.entry_data.ProfilePage[0].graphql.user.edge_owner_to_timeline_media.edges.splice(0, 10)
        for (let media of mediaArray) {
            const node = media.node
            
            followers.push(node.thumbnail_src)
        }
    } catch (e) {
        console.error('Unable to retrieve Followers. Reason: '   e.toString())
    }
    
    return followers
}

Other helpful links: how to write javascript code inside php

https://code.tutsplus.com/tutorials/how-to-use-ajax-in-php-and-jquery--cms-32494