Avoid resetting of position xslt-CodePudding

For each group I have to group by artists having the same number. In the output I have to show the position of the for-each-group (output: 1, 2, 3) but the position resets when entering the second loop of the group and the output currently is (wrong-output:1,2,1).

<xsl:for-each select="group"> <xsl:for-each-group select="artist" group-by="number"> <position> <xsl:value of select="position()"/> </position> <counter> <xsl:value of select="count(number)"/></counter> </xsl:for-each-group> </xsl:for-each>

or

<xsl:for-each select="group"> <xsl:for-each-group select="artist" group-by="number"> <position> <xsl:value of select="position()"/> </position> <counter> <xsl:value of select="count(number)"/></counter> </xsl:for-each-group> </xsl:for-each>

<?xml version="1.0" encoding="UTF-8"?>

<group>
  <artist>
    <number>1</number>
  </artist>
  <artist>
    <number>1</number>
  </artist>
  <artist>
    <number>2</number>
  </artist>
  <artist>
    <number>2</number>
  </artist>
</group>
<group>
  <artist>
    <number>5</number>
  </artist>
  <artist>
    <number>5</number>
  </artist>
</group>

CodePudding user response：

It sounds, based on the wanted output, that you don't need and want the outer for-each and instead directly want to group all artists with e.g.

<xsl:for-each-group select="group/artist" group-by="number">

For your sample data, that would give three groups and the inner <xsl:value of select="position()"/> would that way output the sequence 1, 2, 3.

CodePudding user response：

Here is an example showing how you could number all subgroups consecutively while also keeping their parent groups numbering:

XML

<input>
    <group>
        <item>
            <category>a</category>
        </item>
        <item>
            <category>a</category>
        </item>
        <item>
            <category>a</category>
        </item>
        <item>
            <category>b</category>
        </item>
        <item>
            <category>b</category>
        </item>
    </group>
    <group>
        <item>
            <category>a</category>
        </item>
        <item>
            <category>a</category>
        </item>
    </group>
</input>

XSLT 2.0

<xsl:stylesheet version="2.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>

<xsl:template match="/input">
    <xsl:variable name="groups">
        <xsl:for-each select="group"> 
            <group group-num="{position()}" >
                <xsl:copy-of select="*"/> 
            </group> 
        </xsl:for-each> 
    </xsl:variable>
    <output>
        <xsl:for-each-group select="$groups/group/item" group-by="concat(category, '|', generate-id(..))"> 
            <category group-num="{../@group-num}" subgroup-num="{position()}" >
                <xsl:value-of select="category"/> 
            </category>
        </xsl:for-each-group> 
    </output>
</xsl:template>

</xsl:stylesheet>

Result

<?xml version="1.0" encoding="UTF-8"?>
<output>
   <category group-num="1" subgroup-num="1">a</category>
   <category group-num="1" subgroup-num="2">b</category>
   <category group-num="2" subgroup-num="3">a</category>
</output>