How to return to the same condition if the password is wrong twice-CodePudding

When you input wrong password, incorrect alert show, but second time when you do it, it just let you on site.

var password = "Password123";
          var pass = window.prompt("Enter password: ");
          if (pass == sifra) {
            alert("Correct");
          } else {
            var pass = window.prompt("Incorrect password: ");
          }

CodePudding user response：

You cause your code has no checks after the second prompt. In this scenario, You should write your code in a kind of recursion way. When the password check fails, It should begin the same process again and again until it passes.

// fn: verify the password
function verifyPassword(pass) {
  if (pass === "sifra") {
    alert("Correct");
  } else {
    // prompt the password again if it's incorrect
    promptPassword("Incorrect password: ");
  }
}

// fn: promoting the password
function promptPassword(msg = "Enter password:") {
  var pass = window.prompt(`${msg} `);

  // verify the password
  verifyPassword(pass);
}

promptPassword();

CodePudding user response：

This is happening because second time its just taking input but not validating password if you want to validate password untill its correct you can try this just add a loop

var pass = window.prompt("Enter password: ");
while (pass !== sifra) {
  pass = window.prompt("incorrenct password try again: ");
}
// reaches here only when password is corrent