How to get out of the following enumerate python program as a List-CodePudding

for i,x in enumerate(['A','B','C']):
    print(i, x)

Current output is:

0 A
1 B
2 C

I need the output to be as [(0,A), (1,B), (2,C)]

CodePudding user response：

Just convert the enumerate iterator to a list:

out = list(enumerate(['A','B','C']))

Output:[(0,A), (1,B), (2,C)] (the output is a list object)

If you just want to print:

print(list(enumerate(['A','B','C'])))

Finally, if you're looking to build a string with your specific format, use:

print('[%s]' % ','.join(f'({i},{v})' for i,v in enumerate(['A','B','C'])))

Output: '[(0,A),(1,B),(2,C)]'

CodePudding user response：

Wrap your call to enumerate in a call to list:

out = list(enumerate(['A', 'B', 'C']))

Output:

>>> out
[(0, 'A'), (1, 'B'), (2, 'C')]