I have data like this:
x = c(1,2,3)
prob = c(0.13,0.13,0.74)
# Total sample size
n = 70
result = rep(x, round(n * prob))
Final<-replicate(1, sample(result))
I want to make a matrix[7,10] that have the probability of (0.14,0.14,0.72) for (1,2,3). In this matrix, I need to have in every seven values 1 and 2 repeat 1, and 3 repeats 5 times like this :
3 3 3 1 2 3 3
3 3 3 3 2 1 3
3 2 1 3 3 3 3
3 3 3 1 3 3 2
2 1 3 3 3 3 3
2 1 3 3 3 3 3
3 3 3 2 1 3 3
3 3 3 3 2 3 1
3 2 1 3 3 3 3
So, I will get just one 1, and one 2 in each raw. Could you please help me how to write the code?
CodePudding user response:
One way is to populate a matrix with 3's, then assign 1 and 2 randomly to a column position for each row.
set.seed(1)
m <- matrix(rep(3, 7*10), ncol = 7)
pos <- replicate(10, sample(1:7, 2))
for (i in 1:nrow(m)) m[i, pos[,i]] <- 1:2
m
#> [,1] [,2] [,3] [,4] [,5] [,6] [,7]
#> [1,] 1 3 3 2 3 3 3
#> [2,] 2 3 3 3 3 3 1
#> [3,] 3 1 3 3 2 3 3
#> [4,] 3 3 2 3 3 3 1
#> [5,] 3 2 3 3 3 1 3
#> [6,] 3 3 1 3 3 3 2
#> [7,] 1 3 3 3 2 3 3
#> [8,] 3 2 3 3 1 3 3
#> [9,] 3 3 3 3 3 1 2
#> [10,] 2 1 3 3 3 3 3
Created on 2022-04-15 by the reprex package (v2.0.1)