Extract a simple one from a nested dictionary and sort out elements based on a condition-CodePudding

The following dictionary is given:

dict_nested = {"A":{"C":100, "D":{"E":100, "F":100}}, "B":200}

The result should look like this:

dict_result = {"C":100, "E":100, "F":100, "B":200}

the result should be 1 Dictionary which only contain the key-value pairs, which its values are from type Integer and not dict.
the order should be maintained (i dont mean the alphabetical order of the keys)

CodePudding user response：

Like Sembei said, recursion is needed for this case:

dict_nested = {"A":{"C":100, "D":{"E":100, "F":100}}, "B":200}

def extract_dict(d1, d2):
    for k, v in d1.items():
        if isinstance(v, dict):
            extract_dict(v, d2)
        elif isinstance(v, int):
            d2.update({k: v})

dict_result = {}
extract_dict(dict_nested, dict_result)
print(dict_result)

Output:

{'C': 100, 'E': 100, 'F': 100, 'B': 200}