Enter an If Statement Using Probabilities-CodePudding

I have the function mutateSequence that takes in three parameters. The parameter p is a value between 0 and 1, inclusive. I need two if statements, one that is entered with probability 4p/5 and another that is entered with probability p/5. How do I write the logic to make this happen?

Code:

void mutateSequence(vector<pair<string, string>> v, int k, double p)
{
       for (int i = 0; i < k - 1; i  )
    {
        string subjectSequence = v[i].second;
        for (int j = 0; j < subjectSequence.length(); j  )
        {
            // with probability 4p/5 replace the nucelotide randomly
            if (//enter with probability of 4p/5)
            {
               //do something
            }
            if (//enter with probability of p/5)
            {
                //do something
            }
          
        }
    }
}

I am expecting that the first if statement is entered with probability 4p/5 and the second if statement is entered with probability p/5

CodePudding user response：

There's a very straightforward way to do this in modern C . First we set it up:

#include <random>
std::random_device rd;
std::mt19937 gen(rd());
// p entered by user elsewhere
// give "true" 4p/5 of the time
std::bernoulli_distribution d1(4.0*p/5.0);
// give "true" 1p/5 of the time
std::bernoulli_distribution d2(1.0*p/5.0);

Then when we want to use it:

if (d1(gen)) {
    // replace nucleotide with 4p/5 probability
} else {
    // something else with 1 - 4p/5 probability
}

If instead, you want do one thing with probability 4p/5 and then, independently, another thing with probability 1p/5, that's also easily done:

if (d1(gen)) {
    // replace nucleotide with 4p/5 probability
} 
if (d2(gen)) {
    // something else with 1p/5 probability
}

See bernoulli_distribution for more detail.