If protoc.py is called from powershell, the compiled file is missing about half of the code as opposed to when protoc.py is called from natively from python. I have a powershell script and a python script. My aim is to remove the python script so I only need the powershell script.
My python script is here:
PythonScript.py
import os
from grpc_tools.protoc import main
os.chdir("<MyProtoDirectory>")
main([
'--proto_path=.',
'--python_out=<MyOutputDirectory>',
'--grpc_python_out=<MyOutputDirectory>',
'<MyProto'])
and my powershell script is here:
PowershellScript.ps1
$tmp = (Get-Location).tostring()
Set-Location -Path ('<MyProtoDirectory>')
try {
python '...\protoc.py' `
--proto_path='.' `
--python_out='<MyOutputDirectory>' `
--grpc_python_out="<MyOutputDirectory>" `
"<MyProto>"
}
finally {
Set-Location -Path $tmp
}
I am calling main in python, and the script in powershell, so I modified protoc.py to be:
protoc.py
if __name__ == '__main__':
#proto_include = pkg_resources.resource_filename('grpc_tools', '_proto')
#sys.exit(main(sys.argv ['-I{}'.format(proto_include)]))
a = main(sys.argv[1:])
print(a)
sys.exit()
where I have commented out the altered lines. When I run the python script, I get the result:
outcome_pb.py 67kb
outcome_pb_grpc.py 77kb
When I run the powershell script, I get the result:
outcome_pb.py 28kb
outcome_pb_grpc.py 77kb
The powershell output outcome_pb.py is incorrect and cannot be run, whereas the python outcome is good. It is worth noting outcome_pb_grpc is identical when run using either the powershell script or the python script. Futhermore, I can write a new powershell script that simply calls the python script:
python .\PythonScript.py
and this leads to the same issue. I need both outcome_pb.py and outcome_pb_grpc.py for my application. Why is this happening?
CodePudding user response:
Like DazWilkin said in a comment, it is likely that there is a difference in either the grpcio_tools
library or the Python version you end up using.
To test, you can use some prints:
import sys
import grpc_tools.protoc
print("Python version: %s" % sys.version)
print("grpcio_tools path: %s" % grpc_tools.protoc.__file__)
and compare the output between the working and not-working case.