My date column shows like this: "27 May 2016 10:08:13 AM"
All of my attempts result in a column filled with NA.
I have tried many things like:
df$Create_Month <- format(as.Date(df$`Create Date`, format="%d/%b/%Y %I:%M:%s %p"),"%Y-%m"))
df$Create_Month <- format(as.POSIXct(df$`Create Date`, format="%d/%b/%Y %I:%M:%s %p"),"%Y-%m"))
df[,"Create_Month"] <- format(as.Date(df$`Create Date`, format="%d/%b/%Y %I:%M:%s %p"),"%Y-%m"))
df[,"Create_Month"] <- format(df$`Create Date`,"%Y-%m"))
and variations on these, including dplyr piping, mutate, lubridate and etcetera. Output in Terminal Is:
R> format(df$`Create Date`,"%Y %m"))
Error in format.default(Infocards$`Create Date`, "%Y %m") :
invalid 'trim' argument
R> as.POSIXct("27 May 2016 10:08:13 AM", tz="EST", "%d %b %Y %i:%m:%s %p")
[1] NA
R> as.Date("27 May 2016 10:08:13 AM", "%d %b %Y %i:%m:%s %p")
[1] NA
Any help would be appreciated.
CodePudding user response:
The %i
, %m
, %s
should be upper case
as.POSIXct("27 May 2016 10:08:13 AM", tz="EST", "%d %b %Y %I:%M:%S %p")
[1] "2016-05-27 10:08:13 EST"
With this the format
would work
format(as.POSIXct("27 May 2016 10:08:13 AM", tz="EST",
"%d %b %Y %I:%M:%S %p"), "%Y %m")
[1] "2016 05"
CodePudding user response:
Try parse_date()
function from parse_date
package:
library(parsedate)
parse_date(x)
[1] "2016-05-27 10:08:13 UTC"
CodePudding user response:
import datetime currentDate=datetime.date.today() currentMonthName=currentDate.strftime("%B") print(currentDate) print(currentMonthName)
The strftime() function is used to convert date and time objects to their string representation. It takes one or more input of formatted code and returns the string representation.
%B represent the Full month name like January, February and so on.