How do I match a string pattern until that pattern stops occuring-CodePudding

I have a string that has a specific pattern at the start, that I need to match until it stop occuring, meaning match pattern once until it's broken. The pattern is a digit(s) and a specific (d,h,m,s) character.

For example, 3days 50 seconds 10 min lorem ipsum consectetur adipiscing elit 24 sec sit ametelit has to match 3days, 50 seconds and 10 min, but not 24 sec because it occurs after the pattern was broken.

I have already written a RegEx that matches a digit and character, /\d{1,8}\s*(d|h|m|s)/g. This will match a number of digits at the start, ignore whitespace and then check if a specific character occurs, so it returns these matches 3d, 50 s and 10 m.

However, it matches everything that passes the test, even 24 s, which I don't want it to do. If I remove /g, then it will expectedly return only the first result, which is also undesireable.

CodePudding user response：

const units = ['day', 'days', 'hour', 'hours', 'minute', 'minutes', 'min', 'mins', 'second', 'seconds', 'sec', 'sec']

const regexp = new RegExp(String.raw `(?:\d{1,2}\s*(?:${units.join('|')})\s ) `, 'g')

const text = '3days 50 seconds 10 min lorem ipsum consectetur adipiscing elit 24 sec sit ametelit'

for (const match of text.matchAll(regexp)) {
  console.log(match)
}

You can also match any word

const regexp = /(?:\d{1,2}\s*[a-z] \s ) /g

const text = '3days 50 seconds 10 min lorem ipsum consectetur adipiscing elit 24 sec sit ametelit'

for (const match of text.matchAll(regexp)) {
  console.log(match)
}