Amstrong number return in blank result (java)-CodePudding

public class Amstrong {

    public static void main(String[] args) {

        for (int i = 100; i < 1000; i  ) {

            String a = String.valueOf(i);

            int b = a.charAt(0);

            int c = a.charAt(1);

            int d = a.charAt(2);
            int e = b * b * b   c * c * c   d * d * d;

            if (e == i) {

                System.out.println(i);

            }

        }

    }

}

//Help me out please, no error occurred but the result returned in the blank

CodePudding user response：

You are not converting the characters to digits correctly.

One of the possible ways to fix it:

    int b = a.charAt(0)-'0';

    int c = a.charAt(1)-'0';

    int d = a.charAt(2)-'0';

Another way:

    int b = Character.digit (a.charAt(0),10);

    int c = Character.digit (a.charAt(1),10);

    int d = Character.digit (a.charAt(2),10);

Either way will give your the output:

CodePudding user response：

Another way you can do it is:

import java.util.*;
public class ArmstrongNumber3
{
     public static void main(String args[]) {
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter any number");


        int n = sc.nextInt();

        int b = n;
        int sum = 0;
        int d = 0;
        while (n != 0) {
            d = n % 10;
            sum  = (d * d * d);
            n = n / 10;

        }
        if (sum == b) {
            System.out.println("Armstrong");

        } else
        {
            System.out.println("Not Armstrong");
        }









    }
}