I am looking to create a data.table from a list of unequal vectors, but instead of repeating the values for the "shorter" vector, I want it to be filled with NAs. I have one possible solution, but it repeats values and does not retain the NA as needed.
Example:
library(data.table)
my_list <- list(A = 1:4, B = letters[1:5])
as.data.table(do.call(cbind, my_list))
as.data.table(do.call(cbind, my_list))
A B
1: 1 a
2: 2 b
3: 3 c
4: 4 d
5: 1 e
But I want it to look like:
as.data.table(do.call(cbind, my_list))
A B
1: 1 a
2: 2 b
3: 3 c
4: 4 d
5: NA e
Thank you!
CodePudding user response:
We need to make the lengths
same by appending NA
at the end of the list
elements having lesser length
than the max
length
mx <- max(lengths(my_list))
as.data.table(do.call(cbind, lapply(my_list, `length<-`, mx)))
-output
A B
1: 1 a
2: 2 b
3: 3 c
4: 4 d
5: <NA> e
Instead of cbind/as.data.table
, setDT
is more compact
setDT(lapply(my_list, `length<-`, mx))[]
A B
1: 1 a
2: 2 b
3: 3 c
4: 4 d
5: NA e
CodePudding user response:
You may use stringi::stri_list2matrix
to make all the list length equal.
my_list |>
stringi::stri_list2matrix() |>
data.table::as.data.table() |>
type.convert(as.is = TRUE) |>
setNames(names(my_list))
# A B
#1: 1 a
#2: 2 b
#3: 3 c
#4: 4 d
#5: NA e