Parsing values between double quotes values from json list downloaded via curl-CodePudding

I have an online JSON file. Every time I try to download it. But I need to parse this JSON and get online ip's between double-quotes. Normally I can parse it with jq like .sample[].echo etc. but my list bigger than that example1,2..300 store more than 300 block data in it. I need to parse and get only inside of double quotes and get the all ip's.

By the way: I saw many questions on stackover but none of them related to filtering this kind of input

curl -L "https://sample.data.com/ip.json" -o 'ip.json' | *need to parsing method here*

Here is my JSON file:

{
  "sample1": {
    "echo": [
      "255.254.253.0/32"
    ],
    "delta": [
      "199.231.211.0/32"
    ]
  },
    "sample2": {
    "beta": [
      "250.123.124.0/32"
    ],
    "pre": [
      "122.156.243.0/32"
    ]
  },
  .
  .
  .
  .
  .
}

CodePudding user response：

If you want to extract all strings that looks like an IP, then you can still use jq. If we "fix" your example JSON above, to be actual JSON, then running the following jq program:

.. | strings | match("\\d \\.\\d \\.\\d \\.\\d (?:/\\d )?").string

over it would output:

"255.254.253.0/32"
"199.231.211.0/32"
"250.123.124.0/32"
"122.156.243.0/32"

I guess your don't want to keep the IPs quored, this can be handled with -r output flag

$ curl ... | jq -r '.. | strings | match("\\d \\.\\d \\.\\d \\.\\d (?:/\\d )?").string'
255.254.253.0/32
199.231.211.0/32
250.123.124.0/32
122.156.243.0/32