What is difference between np.copy and np.copy()?-CodePudding

what is difference between np.copy and np.copy() ? I think np.copy() creates copy of numpy array object and np.copy is attribute of the object. But when i try print(np.copy) or print(someObject.copy()) it shows message

'<built-in method copy of numpy.ndarray object at 0x00000214E46468D0>'

<function copy at 0x00000214E2B3BD30>

I'm expecting some value or object. Can you explain to me what is happening here?

edit: What is difference between

SomeObject.copy()

and

SomeObject.copy

CodePudding user response：

Your print just displays the function or method identity. It doesn't run/evaluate either.

If x is an numpy array, np.copy(x) and x.copy() do the same thing.

More generally np.copy(x) will return an array regardless of what x is, while x.copy() uses the copy method defined for the x class. Those may be different.

In [175]: x = np.array([1, 2, 3])
In [176]: np.copy(x)
Out[176]: array([1, 2, 3])
In [177]: x.copy()
Out[177]: array([1, 2, 3])
In [178]: y = [1, 2, 3]
In [179]: np.copy(y)
Out[179]: array([1, 2, 3])
In [180]: y.copy()
Out[180]: [1, 2, 3]

CodePudding user response：

They are two different things. print(np.copy) copies numpy. print(someObject.copy) copies the object. Please upvote this answer to support me