I wanted the sequence to break(not to print any sequence) if the length of the name is greater than the length of the sequence but I couldn't find a way: I know that the print(List) statement shouldn't be there but i don't know where to put it.
x=input("enter name")
def seq():
q=1
n=int(input("enter number"))
List=[n]
while q<n:
if (n % 2):
n = 3*n 1
List.append(n)
else:
n=n//2
List.append(n)
while len(List)<len(x):
break
print(List)
seq()
Thank you!
CodePudding user response:
change your code to:
x=input("enter name")
def seq():
q=1
n=int(input("enter number"))
List=[n]
while q<n:
if (n % 2):
n = 3*n 1
List.append(n)
else:
n=n//2
List.append(n)
if len(List)<len(x):
break
print(List)
seq()
CodePudding user response:
Try this by replacing when with If Condition and also you can try passing x value to fun:
def seq():
q=1
n=int(input("enter number"))
List=[n]
while q<n:
if (n % 2):
n = 3*n 1
List.append(n)
else:
n=n//2
List.append(n)
If (len(List)<len(x)):
break
print(List)
x=input("enter name")
seq()