I have two columns "key" and "time". If the key is same then compare time, keep the minimum time row and drop other with that particular key.
import pandas as pd
data = {
"key": [1,2,3,4,1,2,3,1],
"time": [12.4,12.6,12.8,12.5,12.9,12.3,12.8,12.1],
}
df = pd.DataFrame(data)
print(df)
I tried with duplicate() but it returns series. Tried many other things but didn't work.
CodePudding user response:
You can use groupby over key
and aggregate by minimum as in:
df.groupby(['key']).agg('min')