Obviously, if we write 'x < 10' then, x is smaller than 10. However, it's not the case here

int n;
do
{
    n = get_int("width");
}
while (n < 10);


for (int i = 0; i < n; i  )
{
    printf("?");
}
printf("\n");

If we wanted to print '?' the same number as the user input, it will only print when numbers are larger than 10 while it shouldn't. Because n is not smaller than 10... the loop shouldn't run.

So how is that possible?

CodePudding user response：

...it will only print when numbers are larger than 10 while it shouldn't.

Why shouldn't it? The first loop gets an int from the user, if the user inputs a value that is smaller than 10, it will continue asking the user for a new input, if the user inputs a value larger than or equal to 10 the while loop will end and n will have the input value, then the for loop is executed, if n is, for example, 15, it will run 15 times and consequently print ? 15 times.

CodePudding user response：

The While continue loop until n Is less than 10. Only when n Is 10 or more your program exit from while loop and print.