Can I extract only integers from each line in a string and save them in a list?-CodePudding

I have a string containing 3 lines that looks like this.

@ 544 000
* 600 000
‘7000...

I want to extract these numbers to a list as integers.

Numbers = [544000, 600000, 7000]

I've tried using a for loop splitting the data like this.

numbers = []    
for word in data.split():
    if word.isdigit():
        numbers.append(int(word))
print(numbers)

But the results were

[544, 0, 600, 0]

am I on the right track here,or do I need to split it some other way?

CodePudding user response：

You can use str.isdigit() str.join() (extract every character from the line and check it with str.isdigit(). Join every digit afterwards with str.join()):

s = """@ 544 000
* 600 000
‘7000..."""

for line in s.splitlines():
    print("".join(ch for ch in line if ch.isdigit()))

Prints:

544000
600000
7000

Or as a list:

numbers = [
    int("".join(ch for ch in line if ch.isdigit())) for line in s.splitlines()
]

EDIT: With added checks for lines not containing numbers:

numbers = [
    int(m)
    for line in s.splitlines()
    if (m := "".join(ch for ch in line if ch.isdigit())).isnumeric()
]

CodePudding user response：

The same as @AndrejKesely with a regex:

import re

numbers = [int(''.join(re.findall(r'(\d )', line))) for line in text.splitlines()]

Output:

>>> numbers
[544000, 600000, 7000]