combine two lists of dictionaries of equal length-CodePudding

I'm using Python v3.10.4.

I have two lists of dictionaries that are the same length typically a few hundred lines long, I need to combine them. These lists they represent security indicators of compromise that need to be enriched and fed to a firewall:

uniq = [
    {'uniq-name': '2022-06-26 14:21:25.298167'},
    {'uniq-name': '2022-06-26 14:21:25.298204'}
]
iocvalue = [
    {'value': '116.30.7.55'}, 
    {'value': '31.215.70.187'}
]

I'd like to produce this arrangement:

 summary = [{uniq-name:'2022-06-26 14:21:25.298167', 
 value:'116.30.7.55'}]

I've tried:

 [{[val for val in uniq]   [ val for val in iocvalue]}]

as well as several variations of **uniq, **iocvalue, but I couldn't get it working. What should I do?

CodePudding user response：

You can use a union operation between each pair of dictionaries using a list comprehension and zip(). The syntax for the union operation depends on the Python version:

Python 3.9

[fst | snd for fst, snd in zip(uniq, iocvalue)]

Python <3.9:

[dict(**fst, **snd) for fst, snd in zip(uniq, iocvalue)]

(Note that the dict(**x, **y) syntax is still supported in Python 3.9 , it's just that using | instead is just more concise and readable.)

These output:

[
 {'uniq-name': '2022-06-26 14:21:25.298167', 'value': '116.30.7.55'}, 
 {'uniq-name': '2022-06-26 14:21:25.298204', 'value': '31.215.70.187'}
]

CodePudding user response：

Using a dictionary union operator (Python 3.9 ):

>>> [u | v for u, v in zip(uniq, iocvalue)]
[{'uniq-name': '2022-06-26 14:21:25.298167', 'value': '116.30.7.55'},
 {'uniq-name': '2022-06-26 14:21:25.298204', 'value': '31.215.70.187'}]

For older Python versions:

>>> [{**u, **v} for u, v in zip(uniq, iocvalue)]
[{'uniq-name': '2022-06-26 14:21:25.298167', 'value': '116.30.7.55'},
 {'uniq-name': '2022-06-26 14:21:25.298204', 'value': '31.215.70.187'}]

CodePudding user response：

I hope this can be usefull.

You need to zip both dict:

zipped = zip (uniq,iocvalue)

But zipped is now a 'zip object'

To access it, you can do:

print (*zipped)

Then you get this output:

({'uniq-name': '2022-06-26 14:21:25.298167'}, {'value': '116.30.7.55'}) ({'uniq-name': '2022-06-26 14:21:25.298204'}, {'value': '31.215.70.187'})

CodePudding user response：

summary = []

for i, j in zip(uniq, iocvalue):

   i.update(j)
   summary.append(i)

# Answer: [{'uniq-name': '2022-06-26 14:21:25.298167', 'value': '116.30.7.55'}, {'uniq-name': '2022-06-26 14:21:25.298204', 'value': '31.215.70.187'}]