in python, I want to get all n-digit numbers with digits 1 to n (n <10, each exactly once). How can I ??

Can similar things be done? thanks

CodePudding user response：

You can use itertools.permutations() to get the digits of each number, and then use map() with str() and int() to turn the generated digits into the desired numbers:

import itertools

n = 3
for item in itertools.permutations(range(1, n   1), n):
    result = int(''.join(map(str, item)))
    print(result)

This outputs (only first three / last three lines shown):

123
132
213
231
312
321

CodePudding user response：

Just use itertools.permutations

import itertools

n = 3
for item in itertools.permutations(range(1, n   1), n):
    print(*item, sep='')
    # In case you want to do something with the integer value:
    result = int(''.join(map(str, item)))

Output:

123
132
213
231
312
321