Trying to check if tuple item is nan-CodePudding

I have the below for loop and am try to check first if the tuple(row) item in position 10 is Nan

i=0
for row in df.iterrows():
    if row[1][10] != None:
        names = row[1][10].split(',')
        for name in names:
            df2.loc[i,:] = row[1][:]
            i=i 1
    else:
        i=i 1

I thought I could use if row[1][10] != None: but it doesnt seem to work, anyone know the solution?

CodePudding user response：

Can use pd.isnull(row[1][10]) instead of if row[1][10] != None.

Example:

i=0
for row in df.iterrows():
    if pd.isnull(row[1][10]):
        df2.loc[i,:] = row[1][:]
        i=i 1
    else:
        names = row[1][10].split(',')
        for name in names:
            df2.loc[i,:] = row[1][:]
            df2.loc[i,'name'] = name
            i=i 1

Also please do give feedback about this solution.