How to use parser on multiple time objects-CodePudding

I have an list:

list = ['2022-06-01', '2022-02-02']

Now am using parser to convert this to python date object. like this,

from dateutil import parser

def to_date(value):
    for data in value:
        return parser.parse(data)

Above one gives just one output, but i need the output for both the times and also need to convert that to an string like this:

From : June 1, 2022 | To: Feb. 28, 2022

Is that possible with parser ?

CodePudding user response：

You can use the standard datetime library to perform the parsing. datetime.datetime.strptime allows you to convert a datetime string to a datetime object. datetime.datetime.strftime allows you to convert a datetime object to the desired string.

dt_from, dt_to = [datetime.datetime.strptime(x, "%Y-%m-%d") for x in dt_list]
dt_str = f"From : {datetime.datetime.strftime('%b %d,%Y', dt_from)} | To: {datetime.datetime.strftime('%b %d,%Y', dt_to)}"]

CodePudding user response：

You only get one value back from your to_date function because you exit the function in the first iteration of the loop. You need to introduce an list storing your parsed dates temporary:

from dateutil import parser

def to_date(date_list):
    parsed_date_list = []
    for date in date_list:
        parsed_date_list.append(parser.parse(date))
    return parsed_date_list

date_list = ['2022-06-01', '2022-02-02']
res = to_date(date_list)

Or using a list comprehension to keep your code more concise:

from dateutil import parser

def to_date(date_list):
    return [parser.parse(date) for date in date_list]

date_list = ['2022-06-01', '2022-02-02']
res = to_date(date_list)

And to format your string, simply use the strftime function as pointed out by kpie in his comment:

# res = to_date(date_list)

date_format = "%b %d, %Y"
print(f"From: {res[0].strftime(date_format)} | To: {res[1].strftime(date_format)}")

Do not use list as a variable name. list is a data structure and therefore already in use.