My example array for this problem is:

fruits = [[apples, oranges], [pears, grapes]]

How could I find which array apples is in (fruits[0] or fruits[1]) and then show the value for fruits[0][1] with this information?

(more explanation if needed)

If I were to have the code:

choice = input('Enter a fruit: ')
fruits = [[apples, oranges], [pears, grapes]]
print('The fruit grouped with', choice, 'in the 2D array is', <variable>)

How could I change it to produce the output:

<< Enter a fruit: apples
>> The fruit grouped with apples in the 2D array is oranges

CodePudding user response：

You can check if a string is in an list of strings using in:

'oranges' in ['apples', 'oranges']
# True

You can combine this with a list comprehension and a condition to get a list of items where this condition is True:

fruits = [['apples', 'oranges'], ['pears', 'grapes']]

# for each group in collection
#            |        |
#            V        V
[group for group in fruits if 'grapes' in group]
#                          |___________________| 
#                               | 
# give me that group if the condition is true 

# It's results in a list of lists because there could be more than one
# [['pears', 'grapes']]

If you know there will only be one, you can ask for the next one. Passing None as a second argument give a default. You could also put something like an empty list there if it makes more sense for your problem:

fruits = [['apples', 'oranges'], ['pears', 'grapes']]

choice = 'pears'
next((group for group in fruits if choice in group), None)
# ['pears', 'grapes']

choice = 'oranges'
next((group for group in fruits if choice in group), None)
# ['apples', 'oranges']

choice = 'bannanas'
next((group for group in fruits if choice in group), None)
 # None

CodePudding user response：

You'll need to use a nested for loop so you can go through each item in the 2D array.

So let's say for fruits[basket][fruit]:

• An outer for loop that goes through each basket
• An inner loop that goes through every single fruit item

Then just print out the fruit that is not the user's choice.