My input JSON is like
{
"common": {
"name": "abc"
},
"details": {
"id": 4,
"node": [
{
"name": "node1",
"array2": []
},
{
"name": "node2",
"array2": [
{
"name": "node2_a2_1"
}
]
},
{
"name": "node3",
"array2": [
{
"name": "node3_a2_1"
},
{
"name": "node3_a2_2"
},
{
"name": "node3_a2_3"
}
]
}
]
}
}
What I want is for each leaf node in array2 (e.g. {"name": "node3_a2_1"}
) I will traverse towards the root and add all common items and create an array of JSON objects without any nested object. So, the output I want is like
[
{
"common_name": "abc",
"id": 4,
"node_name": "node2",
"name": "node2_a2_1"
},
{
"common_name": "abc",
"id": 4,
"node_name": "node3",
"name": "node3_a2_1"
},
{
"common_name": "abc",
"id": 4,
"node_name": "node3",
"name": "node3_a2_2"
},
{
"common_name": "abc",
"id": 4,
"node_name": "node3",
"name": "node3_a2_3"
}
]
Could you please suggest how can I do that?
CodePudding user response:
You can walk through the array2
while picking values of each element from their original location in the JSON value.
For example; traverse }
four times to grab the value of id
by using @(4,id)
, and use @(3,name)[&1]
as the common distinguishing identifier for each attribute such as
[
{
"operation": "shift",
"spec": {
"details": {
"node": {
"*": {
"array2": {
"*": {
"@(5,common.name)": "@(3,name)[&1].common_name",
"@(4,id)": "@(3,name)[&1].id",
"@(2,name)": "@(3,name)[&1].node_name",
"name": "@(3,name)[&1].&"
}
}
}
}
}
}
},
{
"operation": "shift",
"spec": {
"*": {
"*": ""
}
}
}
]