Putting items from a dictionary into a string-CodePudding

I want to use data from a list of dictionaries in a string. For example

dict = [{'name':'Matt', 'age':'21'},{'name':'Sally','age':'28'}]

print(f"His name is {??} and he is {??} years old")

I need to know what to replace the question marks with to make it work.

I have looked a lot of stack overflow and found some things, but nothing to get one specific item. I found

print([item["name"]for item in dict])

CodePudding user response：

Iterate over the dicts, and then use the [] operator to get the name and age keys.

people = [{'name':'Matt', 'age':'21'},{'name':'Sally','age':'28'}]

for p in people:
    print(f"Their name is {p['name']} and they are {p['age']} years old")

Their name is Matt and they are 21 years old
Their name is Sally and they are 28 years old

CodePudding user response：

For print all persons in the dict:

for person in dict:
  print(f"His name is {person['name']} and he is {person['age']} years old")

output:

His name is Matt and he is 21 years old
His name is Sally and he is 28 years old

For print one person in the dict, using his index (index 1 in this example):

print(f"His name is {dict[1]['name']} and he is {dict[1]['age']} years old")

output:

His name is Sally and he is 28 years old

CodePudding user response：

dict = [{'name':'Matt', 'age':'21'},{'name':'Sally','age':'28'}]

dict is a list of dictionaries. (Terrible variable name choice, by the way. dict is already the name of something built-in to Python, so by using that as a variable name, you've lost its original meaning. Plus, you're using dict to hold a list of people, so the name itself is not very meaningful. people would be a much better name.)

Lists are accessed by an integer index. So in this case, dict[0] is Matt's entry, and dict[1] is Sally's entry.

Now that you know dict[0] is Matt's entry, you can use the standard dictionary key syntax.

Matt's name is dict[0]['name'] and his age is dict[0]['age'].

Likewise Sally's name is dict[1]['name'] and her age is dict[1]['age'].

(All of this is very basic Python syntax. What part, exactly, did you have trouble with?)