how can i show a misinput in CMD?-CodePudding

i been doing a menu for my class in cmd and i cant make something like a if else structure for it , so even if i give him a wrong input it wont even show a message on the screen, someone know what i can do in this ?

ECHO OFF
CLS
:MENU
ECHO.
ECHO ...............................................
ECHO presione su eleccion :1,2 o 3 para salir
ECHO ...............................................
ECHO.
ECHO 1 - Copia de seguridad y ruta de guardado del respaldo 
ECHO 2 - Cambio de extension de un archivo
ECHO 3 - Salir
ECHO.
ECHO.
SET /P M=presione 1,2 o 3 y presione enter:
IF %M%==1 (GOTO RESPALDO)
ELSE IF %M%==2 (GOTO EXTENSION)
ELSE IF %M%==3 (GOTO EOF)
ELSE (ECHO Opcion no valida 
GOTO MENU)

:RESPALDO
cd %windir%\system32\notepad.exe
start notepad.exe
GOTO MENU
:EXTENSION
cd %windir%\system32\calc.exe
start calc.exe
GOTO MENU

CodePudding user response：

The ELSE must be in the "same" line as the IF (maybe extended by parenthesis ()). So you could write something like this:

IF %M%==1 (GOTO RESPALDO) else (
IF %M%==2 (GOTO EXTENSION) else (
IF %M%==3 (GOTO :EOF) else (
ECHO Opcion no valida 
GOTO MENU
)
)
)

But in this example, you could also dismiss the ELSE:

IF %M%==1 (GOTO RESPALDO)
IF %M%==2 (GOTO EXTENSION)
IF %M%==3 (GOTO :EOF)
ECHO Opcion no valida 
GOTO MENU

BTW: The GOTO :EOF must have the colon, if not it is not found.