I am trying to search a file and count the lines with grep and the following conditions:
- Filter for ACCEPT
- Date of 2018-07-04 OR Date of 2018-08-XX
- Port number of 80 or 443
How do I go about this using grep?
I have the code as:
grep ACCEPT filename | grep -c -e '2018-07-04 \| 2018-08-[1-31]'
CodePudding user response：
You can chain grep commands to achieve an X and (Y or Z) logic, as in grep ACCEPT | grep -c -e '2018-07-04' -e '2018-08-[0-3][0-9]'.
CodePudding user response：
Suggesting to use awk script with RegExp filters pattern logic:
awk '/ACCEPT/ && /2018-07-04|2018-08-[[:digit:]]{2}/ && /80|443/ 1' input.txt | wc -l