How to compare a double to a double value list?-CodePudding

For Example, there is a list containing double values:

[0.017, 0.068, 0.831, 1.034, 1.475, 1.593, 1.746, 2.017, 2.305, 2.695, 3.051, 3.339, 3.627, 3.763, 3.915, 3.966, 4.644, 4.949, 5.085, 5.203, 5.644, 6.136, 6.271, 6.542, 6.712, 7.085, 7.271, 7.661, 7.831, 8.085, 8.390, 8.915, 9.034, 9.492, 9.508, 9.898, 10.271, 10.610, 10.932, 11.169, 11.203, 11.729, 12.186, 12.288, 12.305, 12.644, 13.051, 13.407, 13.458, 13.729, 14.102, 14.525, 14.542, 14.831, 15.136, 15.559, 15.661, 16.169, 16.220, 16.763, 16.780, 17.119, 17.339, 17.390, 18.254, 18.322, 18.525, 18.746]

And there is double value:

0.905

How can we check which is the first number, that is nearer to 0.905 and greater than 0.905 is contained in the above list in flutter?

CodePudding user response：

Try this code

list.firstWhere(
    (element) => element > 0.905,
    orElse: () => 0,
  )

CodePudding user response：

Lets call your list, _list, then we can check it like this:

var result = _list.where((e) => e >= 0.905).toList();
print("result = $result");

CodePudding user response：

I'm using this to get the closest value from a list.

import 'package:collection/collection.dart';

double getClosest(double value, List<double> valueList) {
    final List<double> diffList = valueList
        .map((i) => (i - value).abs())
        .toList();
    return valueList.elementAt(
      diffList.indexOf(diffList.min),
    );
  }

To get the first one which is equal or greater do this:

valueList.where((e) => e >= value).toList()

But keep in mind that the valueList has to be ordered accordingly.

CodePudding user response：

You can use the where clause or a for. check :

final List<double> listDouble = [0.017, 0.068, 0.831, 0.905];
  
  for (int i = 0; i < listDouble.length; i  ) {
    final double myVar = 0.905;
    
    if (myVar == listDouble[i]){
      print ('$myVar finded in position $i');
    }
    
  }

or :

final newDoubleList = listDouble.where((e) => e == myVar);
  
  if (newDoubleList.isNotEmpty){
    print('$myVar finded $newDoubleList');
  }

CodePudding user response：

for simple way you can use following

yourDoubleList.where((element) => element > 0.905).toList()

advanced way

double myDoubleList = [.....]
double value = 0.905 ;

void handle(){
for(double val in myDoubleList  ){
 if(val>=value ){
  print(val) // here you will have all the results that match
}
}
}

CodePudding user response：

       List<double> samleList=[0.017, 0.068, 0.831, 1.034, 1.475, 1.593, 
          1.746, 2.017, 2.305, 2.695, 3.051, 3.339, 
          3.627, 3.763, 3.915, 3.966, 4.644, 4.949, 5.085, 5.203, 5.644, 6.136, 
          6.271.........];
        
        double minDifference =0, givenNumber =0.905;
        int findingIndex =0;
        for(int i =0; i<samleList.length-1; i  ){
        if((samleList[i]>givenNumber) && (samleList[i] - 
 givenNumber<minDifference)){
            minDifference ==samleList[i]-givenNumber;
            findingIndex =i;
        }
                print(samleList[findingIndex]);
    
        }

CodePudding user response：

Try the following code:

List list = [
  0.017,
  0.068,
  0.831,
  1.034,
  1.475,
  1.593,
  1.746,
  2.017,
  2.305,
  2.695,
  3.051,
  3.339,
  3.627,
  3.763,
  3.915,
  3.966,
  4.644,
  4.949,
  5.085,
  5.203,
  5.644,
  6.136,
  6.271,
  6.542,
  6.712,
  7.085,
  7.271,
  7.661,
  7.831,
  8.085,
  8.390,
  8.915,
  9.034,
  9.492,
  9.508,
  9.898,
  10.271,
  10.610,
  10.932,
  11.169,
  11.203,
  11.729,
  12.186,
  12.288,
  12.305,
  12.644,
  13.051,
  13.407,
  13.458,
  13.729,
  14.102,
  14.525,
  14.542,
  14.831,
  15.136,
  15.559,
  15.661,
  16.169,
  16.220,
  16.763,
  16.780,
  17.119,
  17.339,
  17.390,
  18.254,
  18.322,
  18.525,
  18.746,
];

final result = list.where((e) => e >= 0.905).toList()[0];

print(result); // 1.034