leap_year<-function(years) {
if(years>=400 && years%%100==0 && years%%400==0
| years%%100!=0 && years%%4==0) {
print(TRUE)
} else {
print(FALSE) }
}
CodePudding user response:
The lubrdiate
library has the leap_year
function, don't reinvent the wheel.
Try:
library(lubridate)
leap_year<-function(years) {
print(all(leap_year(years)))
CodePudding user response:
you can easiyl check if a year is a leap year with year%4 if a year is dividable with 4 and int is the output its a leap year
i dont't know which language you use i would realize it like this:
if(year%4 == 0){
print(year)
}else{
print("Year is not a leap year)
}
to go through all inputs i would safe them in a array and then go through every element end execute the if this would look like this:
for(int i = 0; i < years.length; i ){
if(year%4 == 0){
print(year)
}else{
print("Year is not a leap year)
}
}
hope i could help